A splitter has two ports on one side, and one port on the other side.
In this case the
two ports are connected to ports A and B of the diseqc switch, and the one port is connected to the long cable, to the 'receiver' port of the second switch.
What happens is this:
If the receiver selects diseqc 1.0 port A, port A of the first switch is chosen, and via splitter and cable arrives at 2nd switch and chooses port A of that switch.
If the receiver selects diseqc 1.0 port B, port B of the first switch is chosen, and via splitter and cable arrives at 2nd switch and chooses port B of that switch.
Switching to port A, a switch always does that automatically: it is its
default port when it receives a voltage. No diseqc repeat needed.
Switching to port B requires a
command repeat in this setup:
First the first switch receives the portB command, and switches to port B.
Now via the splitter and the cable the voltage arrives at switch nr. 2; but that defaults to port A.
After a second port-B command, switch 1 stays in port-B mode, but now switch 2 switches to port B.
QED.
Clearer now?
Greetz,
A33